Subtract 9a^2-6a+5 from 10a^2+3a+25.
Answers
Answer:
I hope it will help you
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
(((9•(a2))-6a)+5)-(((2•5a2)+3a)+25)
STEP
2
:
Equation at the end of step
2
:
((32a2 - 6a) + 5) - (10a2 + 3a + 25)
STEP
3
:
STEP
4
:
Pulling out like terms
4.1 Pull out like factors :
-a2 - 9a - 20 = -1 • (a2 + 9a + 20)
Trying to factor by splitting the middle term
4.2 Factoring a2 + 9a + 20
The first term is, a2 its coefficient is 1 .
The middle term is, +9a its coefficient is 9 .
The last term, "the constant", is +20
Step-1 : Multiply the coefficient of the first term by the constant 1 • 20 = 20
Step-2 : Find two factors of 20 whose sum equals the coefficient of the middle term, which is 9 .
-20 + -1 = -21
-10 + -2 = -12
-5 + -4 = -9
-4 + -5 = -9
-2 + -10 = -12
-1 + -20 = -21
1 + 20 = 21
2 + 10 = 12
4 + 5 = 9 That's it
Answer:
-21,-12,-9,-9,-12,-21, 21, 12, 9
Step-by-step explanation:
That's answer