subtract a^3 - 3a^2 from b^3 - 3b^2
please answer it fast
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Answered by
6
hey friend here is your answer
a3-3a2-b3+3b2
=a3-b3-3(a2-b2)
=(a-b)(a2+b2+ab)-3(a+b)(a-b)
taking common,
=(a-b){a2+b2+ab-3a-3b}
hope it will help you
a3-3a2-b3+3b2
=a3-b3-3(a2-b2)
=(a-b)(a2+b2+ab)-3(a+b)(a-b)
taking common,
=(a-b){a2+b2+ab-3a-3b}
hope it will help you
npVidyashree11:
thank u for ur answer
ur welcome dear
Answered by
12
Hope it will help u......
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