Question

subtract rhe sum of 3 1/9 and 4 1/6 from the sum of 6 2/5 and 7 1/10. ​

Answer 1

Answer:

3.22 or $\frac{26}{9}$ or $2 \frac{8}{9}$

Step-by-step explanation:

According to the question:-

The equation will be $(6 \frac{2}{5} + 7 \frac{1}{10})-(3 \frac{1}{9} + 4 \frac{1}{6})$

• First, make all whole fractions to improper fractions.

$(\frac{32}{5} + \frac{71}{10})-(\frac{28}{9} + \frac{25}{6})$

• Then make all denominators equivalent.

$(\frac{576+639}{90}) - (\frac{280+375}{90})$

According to VBODMAS rule:-

• First solve the brackets.

$\frac{1215}{90} - \frac{955}{90}$

• then solve the subtraction.

$\frac{260}{90}$ = $\frac{26}{9}$ = 3.22 =$2 \frac{8}{9}$

So, $(6 \frac{2}{5} + 7 \frac{1}{10})-(3 \frac{1}{9} + 4 \frac{1}{6})$

= 3.22 or $\frac{26}{9}$ or $2 \frac{8}{9}$

If you liked the answer, please mark my answer as Brainliest.