Subtract the sum of 2x²–3x+7 and -5x²-6x-8 from the product of x+6 and 4x-8
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{(2x²-3x+7)+(-5x²-6x-8)}-{(x+6)(4x-8)}
= (2x²-3x+7-5x²-6x-8)-(4x²-8x+24x-48)
= (2x²-5x²-3x-6x+7-8)-(4x²+16x-48)
= (-3x²-9x-1)-(4x²+16x-48)
= -3x²-9x-1-4x²-16x+48
= -7x²-25x+47
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