Question

Subtract the sum of (8a -6a^2+9) and(-10a-8+8a^2) from -3

Answer 1

Hey friend,
Here is the answer
$sum \: of \: (8a - {6a}^{2} + 9) \: and \: ( - 10a - 8 + {8a}^{2} ) \\ = (8a - {6a}^{2} + 9) + ( - 10a - 8 + {8a}^{2} ) \\ = 8a - {6a}^{2} + 9 - 10a - 8 + {8a}^{2} \\ = 8a - 10a - {6a}^{2} + {8a}^{2} + 9 - 8 \\ = - 2a + {2a}^{2} + 1 \\ \\ subtract \: the \: sum \: from \: - 3 \\ ( - 2a + {2a}^{2} + 1) - ( - 3) \\ = \: - 2a + {2a}^{2} + 1 + 3 \\ = \: 4 - 2a + {2a}^{2}$
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Answer 2

Answer:

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