Geography, asked by toy4, 1 year ago

two trains leave a railway station at the same time. the first train travels due west and the second train due north.the first travels 5km/hr faster than the second train.if after two hours,they are 50km apart ,find the average speedof each train

Answers

Answered by rekhay934
0

Answer:

SolutionLet the speed of the second train = x km/hr

The speed of the first train = x+5 km/hr

Distance covered after two hours by the first train is 2(x+5) km.

Distance covered by the second train after two hours is 2x km.

(2x)^2 + 4(x+5)^2=(50)^2 (Using pythagoras theorem)

Solve

We get x=-20 and x=15

The speed of the first train = 15+5=20km/hr

Explanation:

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Answered by TheMist
48

\huge \sf \color{purple}{\underline{\underline{Answer}}} :

Speed of first train is 20 Km/h and speed of 2nd train is 15 Km/h

\huge \sf \color{purple}{\underline{\underline{Solution}}}:

➣ Let the 2nd train travel at X km/h

➣Then, the speed of a train is (5 +x) Km/hour.

➣ let the two trains live from station M.

➣ Distance travelled by first train in 2 hours

\sf \boxed{\colorbox{skyblue}{Distance=speed×time}} \ \ \ \ \

\ \ \ \ \ \ \ \    = MA = 2(x+5) Km.

➣ Distance travelled by second train in 2 hours

 \ \ \ \ \ \ \ \  = MB = 2x Km

\sf \color{brown}{By \: Phythagoras \: theorem } AB²= MB²+MA²

⟹ 50²=(2(x+5)²+(2x)²

⟹ 2500 = (2x+10)² + 4x²

⟹8x² + 40x - 2400 = 0

⟹x² + 5x - 300 = 0

⟹x² + 20x -15x - 300 = 0

⟹x(x + 20) - 15(x + 20) = 0

⟹ (x + 20)(x -15) = 0

 \sf \boxed{\colorbox{lightgreen}{x=15 \: or \: -20}}

Taking x = 15 , the speed of second train is 15 Km/h and speed of first train is 20 Km/h

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