Question

subtract x+xy+y square from 2x square+3xy

Answer 1

${ \boxed{ \boxed{ \huge{[ {2x}^{2} + 3xy] - [ {(x + xy + y)}^{2} ]}}}} \\ \\ { \boxed{[ {2x}^{2} + 3xy ] - [ {x}^{2} + {y}^{2} + {x}^{2} {y}^{2} + {2x}^{2}y + 2x {y}^{2} + 2xy ] }}\\ \\ { \boxed{{2x}^{2} + 3xy - {x}^{2} - {y}^{2} - {x}^{2} {y}^{2} - {2x}^{2} y - 2x {y}^{2} - 2xy}} \\ \\ { \boxed{ \red{ \small{{x}^{2} - {y}^{2} - {x}^{2} {y}^{2} - {2x}^{2} y - 2x {y}^{2} + xy }}}}$

Answer 2

$\bf( {2x}^{2} + 3xy) - {(x + xy + y)}^{2}$
$\sf => \tiny{( {2x}^{2} + 3xy ) - [{x}^{2} + {x}^{2} {y}^{2} + {y}^{2} + 2( {x}^{2}y + {xy}^{2} + xy )]} \\ \sf = > \tiny{( {2x}^{2} + 3xy ) - [ {x}^{2} + {y}^{2} + {x}^{2} {y}^{2} + {2x}^{2}y + {2xy}^{2} + 2xy ]} \\ \sf = > \tiny{ \underline{{2x}^{2}}+ 3xy - \underline{ {x}^{2}} - {y}^{2} - {x}^{2} {y}^{2} - {2x}^{2} y - {2xy}^{2} - 2xy} \\ \sf = > \red{ \tiny{{x}^{2} } + xy - {y}^{2} - {x}^{2} {y}^{2} - {2x}^{2} y - {2xy}^{2} }$