Sum and difference of the ages of two kids are 9 and 1 respectively how long ago were their ages in the ratio 3:2
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Answer:
Step-by-step explanation:
Let the ages be x ,y
Therefore
Ages are 3x and 2y respectively
According to the 1st condition
3x + 2y = 9.........1
According to the 2nd condition
3x - 2y = 1............2
By elimination method
Add equation 1and 2
Therefore equation will be
6x = 10
x = 10/6
x= 1.6
Put value of x in equation 1
3(1.6)+2y= 9
4.8+2y= 9
2y=9-4.8
2y= 4.2
y=1.2
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