Math, asked by Fighters5625, 9 months ago

Sum and difference of the ages of two kids are 9 and 1 respectively how long ago were their ages in the ratio 3:2

Answers

Answered by 28mahekdugad58
0

Answer:

Step-by-step explanation:

Let the ages be x ,y

Therefore

Ages are 3x and 2y respectively

According to the 1st condition

3x + 2y = 9.........1

According to the 2nd condition

3x - 2y = 1............2

By elimination method

Add equation 1and 2

Therefore equation will be

6x = 10

x = 10/6

x= 1.6

Put value of x in equation 1

3(1.6)+2y= 9

4.8+2y= 9

2y=9-4.8

2y= 4.2

y=1.2

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