Math, asked by ashwaniverma2948, 11 months ago

The ages of x and y are in the proportion of 6:5 and total of their ages is 44 years. The proportion of their ages after 8 years will be

Answers

Answered by Anonymous
37

Given that,

The proportion of the present ages of x and y is 6 : 5

Let their ages be 6a and 5a respectively.

Total of their ages = 44 years

➡ x + y = 44 years

➡ 6a + 5a = 44 years

➡ 11a = 44 years

➡ a = 44/11

➡ a = 4 years

Therefore their present ages :-

  • x = 6a = 6 × 4 = 24 years

  • y = 5a = 5 × 4 = 20 years

After 8 years their ages will be :-

  • x = 24 + 8 = 32 years

  • y = 20 + 8 = 28 years

Hence, proportion of their ages after 8 years = 32/28

= 8 : 7 final answer

Answered by Anonymous
16

Given :-

The age of x & y are in proportion = 6:5

Total age = 44 years

To Find :-

Proportion of their ages after 8 year = ?

Solution :-

Let the present age of x & y be 6p & 5p respective.

According to the given condition,

x + y = 44 yrs

6p + 5p = 44 yrs

11p = 44

p = 44/11

P = 4

Substituting the value of p = 4

Therefore,

6p

6(4) = 24 yrs

5p

5(4) = 20 yrs

After 8 year there age will be

x + 8 -> 24 + 8 = 32 yrs

y + 8 -> 20 + 8 = 28

Therefore, the proportion of their age after 8 years will be

= 32/28

= 8/7

= 8: 7

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