sum and product of zero of p(x)=2(x^2-3)+x
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Answered by
0
On expanding, the equation becomes
2x² + x - 6
This equation can now be seen in form ax² + bx + c
Now,
Sum of roots = -b/a
= -1/2
& Product of roots = c/a
= -6/2 = -3
2x² + x - 6
This equation can now be seen in form ax² + bx + c
Now,
Sum of roots = -b/a
= -1/2
& Product of roots = c/a
= -6/2 = -3
Answered by
1
Heya,
Here is the required solution:-
2(x^2-3)+x can be simplified as:
2x^2-6+x
= 2x^2+x-6
This is an quadratic equation of the form ax^2+bx+x
So ,
The Sum of the zeros = Alpha + beta
= -b/a
= -1/2
The product of the zeroes = Alpha×beta
= c/a
=-3
Hope it helps u...
Here is the required solution:-
2(x^2-3)+x can be simplified as:
2x^2-6+x
= 2x^2+x-6
This is an quadratic equation of the form ax^2+bx+x
So ,
The Sum of the zeros = Alpha + beta
= -b/a
= -1/2
The product of the zeroes = Alpha×beta
= c/a
=-3
Hope it helps u...
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