sum of 15 terms of an AP is 600, and the common difference is 5. find the first term
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Tn = a + (n-1)d
T15 = a + (15-1) 5
600 = a + 14* 5
600 = a + 70
a = 600- 70
a = 530.
the first term of an AP is 530.
hope it helps
Thanks..
T15 = a + (15-1) 5
600 = a + 14* 5
600 = a + 70
a = 600- 70
a = 530.
the first term of an AP is 530.
hope it helps
Thanks..
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