Question

sum of 1st and 3rd term of an A.P is 8.and sum of 2nd and 4th terms are 12. find 1st term.

Frnds plzz make it fast​

Answer 1

Answer:

Step-by-step explanation:

8=a+(4-1)4 when 1st term is a and common difference is 4. Then a=8-3×4=8-12=-4. Likewise 2nd term is 0. If they belong G.P then common ratio is 2 and 1st term is a. Then 4=a×2^(3-1)=a×2^2=4a , so a=4/4=1 and like wise 2nd term is 1×2=2.

Ans: In case of A.P:-4,0 & in case of G.P :1 & 2.

Answer 2

Answer:

2

Step-by-step explanation:

a+(a+2d)=8

(a+d)+(a+3d)=12

2a+2d=8

2a+4d=12

Solving the equations we get,

2d=4

d=2

a=2

The first term is 2