Sum of 21a35 and 29096 is 50b31 is divisible by 11
Answers
Answered by
0
50b31 is divisible by 11
It means that 5 + b + 1 - 0 - 3 is divisible by 11 i.e. 3 + b is divisible by 11
As b varies from 0 to 9, so, 3 + b = 11
b = 8
21a35 + 29096 = 50831
21a35 = 21735
a = 7
So, a = 7 and b = 8
Similar questions