Question

sum of 3 consecutive multiples of 11 is 330 find the multiples

Answer 1

Let the first number be 11a

Second number = 11a + 11

Third number = 11a + 22

=> 11a + 11a + 11 + 11a + 22 = 330

=> 33a + 33 = 330

=> a + 1 = 10

=> a = 9

First number = 99

Second number = 110

Third number = 121

Answer 2

Let the multiples be 11x, 11(x+1) and 11(x+2)

so,

11x + 11(x+1) + 11(x+2) = 330
11x + 11x + 11 + 11x + 22 = 330
33x + 33 = 330
33x= 330 - 33
x = 297/ 33 = 9

First multiple = 11 * 9 = 99
Second multiple = 11* 10 = 110
Third multiple = 11 * 11 = 121