Question

Sum of 3 consecutive terms of an arithmetic progression is 15 and the sum of their square is 83 . find the numbers?

Answer 1

Yo!

Here's the answer!

Let the numbers be=a,a+d,a-d

So,a+a+d+a-d=15.

Therefore, 3a=15.

a=5.

(a)^2+(a+d)^2+(a-d)^2=83.

Therefore,25+50+2d^2=83.

Hence,2d^2=8.

d=+2,-2.

∴The numbers are 3,5,7.

Hope that this helps you!

-TGA.