Question

Sum of a number and its half if 30 then the number is?

Answer 1

Answer:

x=20

Step-by-step explanation:

x+x×1/2=30

=x+x/2=30

change into same denominator by =x×2/1×2+x/2=30

=2x/2+x/2=30

=2x+x/2=30

=3x/2=30

=3x=30×2=60

=x=60/3=20

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Answer 2

Answer:

Required number is 20.

Step-by-step explanation:

Given,Sum of a number and its half if 30.

Let the number be a

According to question,

$a + \frac{a}{2} = 30 \\ \frac{3a}{2} = 30 \\ 3a = 2 \times 30 \\ 3a = 60 \\ a = \frac{60}{3} \\ a = 20$

So, required number is 20.

This is a problem of equation part of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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