sum of all the first 'n' terms of even natural number is,.......
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Answered by
12
2,4,6
a=2 d=2
Sn=n/2(2a+(n-1)d)
=n/2(2×2+(n-1)2)
=n/2(4+2n-2)
=n/2[2(n+1)]
=n(n+1)
=n²+n
a=2 d=2
Sn=n/2(2a+(n-1)d)
=n/2(2×2+(n-1)2)
=n/2(4+2n-2)
=n/2[2(n+1)]
=n(n+1)
=n²+n
rathodbhaskar08:
n(n+1) is not
it is right bro
take ex.b 2,4,6
what are you asking? I am not able to understand that
3(3+1)=12
ans
2+4+6=12
understand
Answered by
6
sum of evennatural no. n(n+1)
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