Question

sum of all the first 'n' terms of even natural number is,.......

Answer 1

2,4,6
a=2 d=2
Sn=n/2(2a+(n-1)d)
=n/2(2×2+(n-1)2)
=n/2(4+2n-2)
=n/2[2(n+1)]
=n(n+1)
=n²+n

Answer 2

sum of evennatural no. n(n+1)
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