Question

sum of area of two square is 369 m² in the difference of their perimeter is 12 m² find the side of two square​

Answer 1

Answer:

12 and 15

Step-by-step explanation:

sum of areas implies

a^{2} + b^{2} = 369  -------> eq 1

difference in perimeters implies

4a -4b = 12

4(a-b) =12

a-b =3 -----------> eq2

Substitute eq2 in eq1

(3+b)^{2} + b^{2} = 369

9 + 6b + b^{2} + b^{2} = 369

9 + 6b + 2b^{2} = 369

------> b = -15, 12

eq2 ------> a= -12, 15

since the length of sides cannot be negative

sides are 12, 15

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