Sum of digits in a two digit number is 9. If 27 is subtracted from the number,digits of the number are interchanged. Find the original number.
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here is your answer by Sujeet,
Let to be 10' unit be x
Let to be 1'unit be y
then,
Original number=10x+y
Digit interchange no.=10y+x
x+y=9----(2)
then
@/q
10x+y-27=10y+x
10x-x+y-10y=27
9x-9y=27
9(x-y)=27
x-y=27/9
x-y=3 -------(3)
Now solving
this question by elimination method,
x+y=9
x-y=3
_____
2y=6
y=6/2
y=3
then,
Now putting the value of y in another equation,
x+y=9
x+3=9
x=¶-3
x=6
Now,
Original number be 10x+y
10*6+3
60+3
63
that's all
Let to be 10' unit be x
Let to be 1'unit be y
then,
Original number=10x+y
Digit interchange no.=10y+x
x+y=9----(2)
then
@/q
10x+y-27=10y+x
10x-x+y-10y=27
9x-9y=27
9(x-y)=27
x-y=27/9
x-y=3 -------(3)
Now solving
this question by elimination method,
x+y=9
x-y=3
_____
2y=6
y=6/2
y=3
then,
Now putting the value of y in another equation,
x+y=9
x+3=9
x=¶-3
x=6
Now,
Original number be 10x+y
10*6+3
60+3
63
that's all
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