Sum of distances fromA(3,4) to x axis from B(3,2)to y axis is
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Answer:
✿distance b/w AB =√ (x2-x1)^2 + (y2-y1)^2
= √(3-3)^2 + (2-3)^2
= √ 0 + (-1)^2
= ✓1
༎ຶ‿༎ຶ༎ຶ‿༎ຶ༎ຶ‿༎ຶ
✷so the distance b/w two pts AB is √1
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