Question

sum of first 50 odd natural numbers

Answer 1

the sum is

1+3+5+7+...........50 terms

there fore the given series is in arthimetic progression where a=1,d=2,n=50

sum is n/2(2a+(n-1)d)

by substituting

25(2+98)

2500

so the sum of first 50 odd numbers is 2500


I hope this will help u ;)

Answer 2

Answer:

1. formula is used n/2(2a+(n-1)d)

A.P is = 1,3,5,7....50wherea=1 ,d=2 ,n=50by

using formula we get

50/2(2)+(50-1)2)

25(4+49×2)

25(53×2)

25(106)

2650 ANSWERI

hope this will help you,,,,,