sum of first term sn=3n^2+29 find an first term of ap
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put n=1 to find the first term in sn that would be 32
Anonymous:
ur welcome rajkumar
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hii friend ......
sn=3n^2-+9
s1=3*(1)^2+29
s1=3+29..
s1=32...s1=t1...........we can say that.....☺Ans.....
hope it help
.
@Rajukumar☺☺☺
sn=3n^2-+9
s1=3*(1)^2+29
s1=3+29..
s1=32...s1=t1...........we can say that.....☺Ans.....
hope it help
.
@Rajukumar☺☺☺
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