Question

sum of the areas two squares is 468 meter squares. if the difference of their perimeter is 24 m, find the sides of the two squares.
send me solution...​

Answer 1

Answer:

12 and 18

Step-by-step explanation:

let side of one be x and other be y

x square + y square = 468

also

4x- 4y=24

x - y = 6

x = 6+y (since side is perimeter divided by 4)

(6+y)square + y square = 468

solve this and we will get y = 12

then x = y+6 = 18

Answer 2

Answer:

a=18m   b=12m

Step-by-step explanation: