Question

sum of the digit of a two digit number is 9. when we interchange the digits, it is found that the resulting number is greater than the original number by 27. what is the two Digit number

Answer 1

let ones place digit = x
then tens place digit = 9-x
now number became = 10 (9-x)+x =90-10x+x =90-9x
After interchanging the no. became =100 + 9 -x = 9x +9
A T Q
90-9x+27 = 9x + 9
9x + 9x = 9 -27-90
18 x = 108
x = 108/18
x = 6
now
ones place digit = 6 &
tens place digit = 9-x = 9-6 =3
hence the required no. is 36.
hope this will help you and please mark me as brainliest.

Answer 2

● Let the digit at unit place = X

● So digit at tens place = 9-X

» Now

● Original Number = 10(9-X) + X = 90 - 9X

● When the digit are reversed then new number = 10(X) + (9-X) = 9X + 9

_____________

» Now

● According to question :-

=> 9X + 9 = 90 - 9X + 27

=> 18X = 108

=> X = 108/18 = 6

________________

● thus the unit digit = 6

» and

● tens digit = 9-6= 3

________________

● thus the Original number is "36"

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