sum of the digits of a two digit number is 10 on interchanging the digits the number obtained is 54 less than the original number find the orginal number
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Let X be the no in unit place
and y be the no in tenth place
X+Y=10
probabilities=1+9/2+8/3+7/4+6
The actual no and digits interchanged no must have a difference of 54
28 agrees with this factor
82_28=54
and y be the no in tenth place
X+Y=10
probabilities=1+9/2+8/3+7/4+6
The actual no and digits interchanged no must have a difference of 54
28 agrees with this factor
82_28=54
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