Question

sum of the digits of a two digit number is 11 if the digits are interchanged the digit it is found that the resulting new number is greater than the original number by 63 find the two digit number

Answer 1

hey dude here is ur answer....!!!


Let the tens digit be x and the ones digit be y .
x + y = 11 … (1)
Original number = 10 x + y
Reverse number = 10 y + x
Given, Reverse number = Original number + 63
∴10 y + x = 10 x + y + 63
⇒ 9 y – 9 x = 63
⇒ y – x = 7 … (2)
Adding (1) and (2),
x+y = 11
-x+y=7
2y=18
⇒ y = 9
When y = 9,
x + 9 = 11 (Using (1))
x = 11 – 9 = 2
∴ Original number = 10 x + y = 20 + 9 = 29.

thanks... !

Answer 2

two digit no is -15 of above question