sum of the squares of two consecutive odd natural number is greater than 8 times their sum by 2 find the number
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Step-by-step explanation:
→ Let consecutive odd natural numbers be x, x+2
→ According to the question,
→ x²+(x+2)²=8(x+x+2)+2
→ x²+x²+4+4x=16x+16+2
→ 2x²+4x-16x=18-4
→ 2x²-12x-14=0
→ x²-6x-7=0
→ x²-7x+x-7=0
→ x(x-7)+1(x-7)=0
→ Now value of x=7
→ The two consecutive odd natural numbers are 7,9
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