Question

Sum Of The two zeroes of a polynomial of degree 4 is -1 and their product is -2. If other two zeros are root3 and -root 3. Find the polynomial

Answer 1

hey mate here is your answer

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Answer 2

let a b c d be the roots of biquadratic polynomial

given a+ b = -1

ab=-2

given c= root 3 d= - root 3

c+d = 0

cd=-3

let b= -2/a substitute we get a=1 or -2 then b= either -2or 1

consider a=1 b= -2 c= root 3 d= - root3

a+b+c+d= 1-2+0=-1 =-b/a

ab+bc+cd+ac+ad+bd = -2 -2root3 -3+root3-root3 +2root3 = -5

abc+acd+bcd+abd = -2root3 -3+6 +2root3 =3

abcd= 6

req. polynomial = x^4+1x^3-5x^2-3x +6