sum of three consative integers is 24 find the integer
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Answered by
5
Let us assume 3 consecutive integers as x, x+1 and x+2.
ATP,
x+x+1+x+2=24
3x+3=24
3x=24-3
3x=21
x=21/3
x=7
Therefore the 3 consecutive integers are 7,8 and 9.
ATP,
x+x+1+x+2=24
3x+3=24
3x=24-3
3x=21
x=21/3
x=7
Therefore the 3 consecutive integers are 7,8 and 9.
Answered by
4
Let the unknown numbers be x , x+1 , x+2.
Given,
Sum of three consecutive intergers is 24.
: x + (x+1) + (x+2) = 24
3x + 3 = 24
3x = 24 - 3
3x = 21
x = 21/3
x = 7
x = 7
(x+1) = 7+1 = 8
(x+2) = 7+2 = 9
The three consecutive intergers are 7 , 8 and 9.
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Then square the numbers, and multiply the results together (product). So with the numbers above:
3^2 = 9
4^2 = 16
5^2 = 25
9*16*25 = 3600