sum of three consecutive multipes of 9 is 999 find their multiples
Answers
Answered by
1
Hey mate,
Here's your answer.. ☺
Lets suppose the first multilple of 9 among those three consecutive multiples is (x-9).
Lets suppose the second consecutive multiple of 9 is x.
Let suppose the third consecutive multiple of 9 is (x+9).
Since according to the question,
the sum of three consecutive multiple is 999.
=> (x-9) + x + (x+9) = 999
=> 3x = 999
So the first consecutive multiple = x - 9 = 324.
So the second consecutive multiple = x = 333.
So the third consecutive multiple = x + 9 = 342.
So the required multiples of 9 are 324, 333, 342.
Hope it helps. ❤
@berryBlue
Similar questions