Question

sum of three consecutive multiples of 8 is 888

Answer 1

Let the multiples are :-

8x, (8x+8) and (8x+16)
________________________

8x + 8x +8 +8x + 16 = 888

8x + 8x + 8x + 8+16 = 888

24x + 24 = 888

24x = 888 -24

 24x =864

 x = $\frac{864}{24}$

x = 36

__________________________

Multiples are :-

8x = 8 ×36  = 288

8x + 8 = 288 + 8 =296

8x + 16 = 288 + 16 =304

___________________

Multiples are :-

288, 296 and 304




i hope this will help you


-by ABHAY

Answer 2

Heya ✋

Let see your answer !!!!

Let the sum of 3 consecutive multiples of 8 be 8x , 8(x + 1) and 8(x + 2). Then,

according to question ,

8x + 8(x + 1) + 8(x + 2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

=> 24x = 888 - 24

=> 24x = 864

=> x = 864/24

=> x = 36

Hence , 1st multiples of 8 = 8 × 36 = 288

2nd multiples of 8 = 8(36 + 1)

= 8 × 37

= 296

3rd multiples of 8

= 8(36 + 2)

= 8 × 38

= 304





Thanks :))))