Question

sum of three consecutive terms of AP is 48. in this AP product of first and last term is 252, then d=?​

Answer 1

Step-by-step explanation:

let the. first term of Ap is a then 2nd term is a+d and 3rd rem is a+2d

a+a+d+a+2d=48

3a+3d=48 then

a+d =16

d=16-a. -(i)

a*(a+2d)=252

from eq 1

a(a+2(16-a))=252

aage khud solve kro

Answer 2

Answer:

Step-by-step explanation:

always the three consecutive number is in the form of (a-d) , a , (a+d)

so the sum of three terms is = 48

(a-d) + a+(a+d) = 48

3a=48

a=48/3

a=16

now the product of first and third term is = 252

(a-d) x (a+d) = 252

a²-d²= 252

(16)²-d²=252

256-d²=252

d² = 256 - 252

d²=4

d=√4

d=2