Question

sum of two angles of a triangle is 90° and their difference is 50° . find all the angles of the triangle

Answer 1

70,20 and 90 degrees

Answer 2

let the angles be a ,b and c 
a+b+c=180 degrees {angle sum prop of triangle}
a+b=90{given}...............................(1)
a-b=50{given}.................................(2)

solving equations 1 and 2 gives,

2a=140               (b gets cancelled and the sum of 90 and 50 equals to 140)
therefore a =140 divided by 2
                   =70
substituting it in eq.1 ,
70 +b=90
       b=90-70
         =20
<A+<B+<C =180 
  70+20+<C=180
              < C=180-(70+20)
                    =180-90
                    =90
therefore the angles are 90, 70 and 20