sum of two consecutive even natural number is 24 . find the number
Answers
they are 16 and 8
hope it helps
Let 2n = the first even number, where n is an integer, and ...
Let 2n + 2 = the second consecutive even number, and
Let 2n + 4 = the third consecutive even number.
Since the sum of the three unknown consecutive even numbers is 24, we can write the following equation to be solved for n as follows:
2n + (2n + 2) + (2n + 4) = 24
2n + 2n + 2 + 2n + 4 = 24
2n + 2n + 2n + 2 + 4 = 24
Collecting like-terms on the left, we get:
6n + 6 = 24
6n + 6 - 6 = 24 - 6
6n + 0 = 18
6n = 18
(6n)/6 = 18/6
(6/6)n = 18/6
(1)n = 3
n = 3
Therefore, ...
2n = 2(3) = 6 and
2n + 2 = 6 + 2 = 8 and
2n + 4 = 6 + 4 = 10
CHECK:
2n + (2n + 2) + (2n + 4) = 24
6 + (8) + (10) = 24
6 + 8 + 10 = 24
14 + 10 = 24
24 = 24
Therefore, the three desired consecutive even numbers whose sum is 24 are indeed 6, 8, and 10, and the median or middle value is plainly 8.