Sum of two consecutive multiples of 5 are 215. Find the smallest one.
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Let 5x be the smallest multiple of 5.
Then, the three consecutive multiples shall be 5x, 5x+5 and 5x+10
According to the question,
5x+5x+5+5x+10=45
∴5x+5x+5x=45−15
∴15x=30
∴x=2
∴ Smallest multiple =5x=5×2=10
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