Sum of two digit is 22 and sum of squares of these digit is 404, then what will be the multiplication of these digit?
sivaprasath:
40 is your answer
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x+y= 22
x²+y²= 404
(x+y)²= x²+y²+2xy
or,(22)²=404+2xy
or,484-404 = 2xy
or,80/2= xy
or, xy= 40
now
(x-y)²= (x+y)²-4xy
(x-y)²=484-160
(x-y)²=324
(x-y)=18. ------eqn1
(x+y) =22. -------eqn 2
now solve both eqn
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