Sum of two digit number is 1 2 if the new number formed by reversing the digits is greater than the original number by 54 find the original number.
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Let the tens place digit be a
And unit place digit be b
According to first condition,
a + b = 12 -----(1)
According to second condition,
(10b + a) - (10a +b) = 54
=> 9b - 9a = 54
=> b- a = 6 ----- (2)
On adding equation (1) and (2), we get
2b = 18
=> b = 9
On putting the value of b in equation (1), we get
a + 9 = 12
=> a = 3
Required number = 39
And unit place digit be b
According to first condition,
a + b = 12 -----(1)
According to second condition,
(10b + a) - (10a +b) = 54
=> 9b - 9a = 54
=> b- a = 6 ----- (2)
On adding equation (1) and (2), we get
2b = 18
=> b = 9
On putting the value of b in equation (1), we get
a + 9 = 12
=> a = 3
Required number = 39
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