Question

sum of two number is 34 one no is exceed another by. 7 find the Number? ​

Answer 1

Answer:

The numbers whose sum is 34 and difference is 7 are 13.5 and 20.5.

Step-by-step explanation:

Let the two numbers be x and y.

Sum of the two numbers is 34. That is,

       x + y = 34  

Let the above equation be equation 1.

One number exceeds the other by 7. Let y be the bigger number. Therefore

       x + 7 = y                  

Or,   y = x + 7

Let the second equation be equation 2.

Substituting the value of y of equation 2 in equation 1, we get

      x + x + 7 = 34

     2x + 7 = 34

     2x = 27

     x = 13.5

Substituting this value of x in equation 2, we get

      y = 13.5 + 7

         = 20.5.

Hence the numbers are 13.5 and 20.5.

Answer 2

Answer:

x = 20.5

y = 13.5

Step-by-step explanation:

let us take the first number as = x

let us take second number as = y

exceeds means difference

x + y = 34 ------------  (1)

x - y = 7 ---------------- (2)

Let us try to solve by elimination method

by adding (1) and (2)

   x + y = 34

   x - y = 7

-------------------

2x = 41

x = 41/2

x = 20.5

x + y = 34

20.5 + y = 34

y = 34 - 20.5

y = 13.5