Question

Sum of two numbers is 22. Product of the number is 118
more than their difference, find the product of th
numbers.​

Answer 1

let the numbers ==> x & y

x+y = 22 —(1)
xy= 118 + ( x-y ) —-(2)


from (1) , x= 22-y

substitute in (2)

(22-y)y = 118 + 22-y -y
22y -y ^2 = 118 + 22 -2y
= 140-2y
140-2y-22y+y^2 = 0 ( after transposing)
y^2 -24y + 140 = 0

a+b = -24
ab = 140
a = -14
b = -10

y^2 -14y -10y +140
y(y-14) -10(y-14)
(y-10)(y-14)


so y ==> 10 or 14

when y = 10 , x = 22-y = 12
when y = 14 , x = 22-14 = 8

Answer 2

Answer:

x=10.y=12

x*y =120