Sum of two numbers is 45.And product of it is 125 find sum of reciprocal
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Answered by
1
x+y=45
xy=125
(1/x)+(1/y)=(x+y)/xy
=45/125
=9/25
xy=125
(1/x)+(1/y)=(x+y)/xy
=45/125
=9/25
Answered by
5
THANKS FOR THE QUESTION !
_______________________________
GIVEN :
SUM OF TWO NO. :
=> 45
PRODUCT OF TWO NO. :
=> 125
_____________________________
TO FIND :
=> SUM OF THEIR RECIPROCALS :
_____________________________
LET,
=> FIRST NO. BE :
=> X
_____________________________
2ND NO . BE :
=> Y
_____________________________
FROM THE INFO :
=> X + Y = 45
=> X * Y = 125
_____________________________
THE RECIPROCAL OF X :
=> 1 / X
_____________________________
THE RECIPROCAL OF Y :
=> 1 / Y
_____________________________
SUM OF THEIR RECIPROCALS :
=> 1 / X + 1 / Y :
=> 1 * Y + 1 * X / X * Y
=> X + Y / X * Y
______________________________
=> BUT WE HAVE THE VALUES OF X + Y AND X * Y
______________________________
SUM OF RECIPROCALS :
=> 45 / 125
=> 9 / 25
_____________________________
HOPE IT WILL HELP U ......
THANKS AGAIN ........
_____________________________
_______________________________
GIVEN :
SUM OF TWO NO. :
=> 45
PRODUCT OF TWO NO. :
=> 125
_____________________________
TO FIND :
=> SUM OF THEIR RECIPROCALS :
_____________________________
LET,
=> FIRST NO. BE :
=> X
_____________________________
2ND NO . BE :
=> Y
_____________________________
FROM THE INFO :
=> X + Y = 45
=> X * Y = 125
_____________________________
THE RECIPROCAL OF X :
=> 1 / X
_____________________________
THE RECIPROCAL OF Y :
=> 1 / Y
_____________________________
SUM OF THEIR RECIPROCALS :
=> 1 / X + 1 / Y :
=> 1 * Y + 1 * X / X * Y
=> X + Y / X * Y
______________________________
=> BUT WE HAVE THE VALUES OF X + Y AND X * Y
______________________________
SUM OF RECIPROCALS :
=> 45 / 125
=> 9 / 25
_____________________________
HOPE IT WILL HELP U ......
THANKS AGAIN ........
_____________________________
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