Question

sum of two numbers is 85. if one number exceed the other by 5 find the smallest of theses numbers.

Answer 1

Answer:

$let \: the \: no \: be \: x \\ 1st \: no = x \\ 2nd \: no = x + 5 \\ now \\ x + x + 5 = 85 \\ 2x + 5 = 85 \\ 2x = 80 \\ x = \frac{80}{2} \\ x = 40$

40 is the answer

Answer 2

hello dear
here is ur answer

The smallest no. is 40


Thankyou ☺

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