Question

Sumit, Akshay and Ruchi prepared 200 g salt solution each in beaker 'A', 'B' and 'C' with concentration (% w/w) 15%, 12% and 10% respectively. Ruchi evaporated 100 g of water from beaker 'C' and the concentration of solution changes to x% from 10%. Rohit took 10 g solution from beaker 'A', 15 g solution from beaker 'B' and 20 g solution from beaker 'C' (after evaporation) and mixed in another beaker 'D'. The percentage concentration (w/w) of solution in

beaker 'D' is
A) 15%

B) 15.87%

C.18.68%

D) 16.22%
​​

Answer 1

Given : Sumit, Akshay and Ruchi prepared 200 g salt solution each in beaker 'A', 'B' and 'C' with concentration (% w/w) 15%, 12% and 10% respectively

Ruchi evaporated 100 g of water from beaker 'C' and the concentration of solution changes to x% from 10%.

Rohit took 10 g solution from beaker 'A', 15 g solution from beaker 'B' and 20 g solution from beaker 'C' (after evaporation) and mixed in another beaker 'D'

To Find :  The percentage concentration (w/w) of solution in beaker 'D'  

A) 15%

B) 15.87%

C.18.68%

D) 16.22%

Solution:

10 g solution from beaker 'A', with concentration (% w/w) 15%

concentration = (15/100)10  = 1.5g

Water = 10 - 1.5 = 8.5 g

15 g solution from beaker 'B', with concentration (% w/w) 12%

concentration = (12/100)15 = 1.8g

Water = 15 - 1.8 =13.2 g

Beaker C 200 g  - concentration (% w/w)  10%  

concentration = (10/100)200  =20g

Water = 200 - 20 = 180g

Water evaporated = 100 g

So solution in beaker C

concentration = 20 g  and  water = 80 g  => mixture = 100 g

20 g solution from beaker 'C'  

Concentration = (20/100)20 = 4 g

1.5 + 1.8 + 4  = 7.3 g concentration

Total = 10 + 15 + 20  = 45 g

% Concentration  = (7.3/45) * 100 =  16.22 %

D) 16.22%  is correct answer

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Answer 2

Explanation:

above answer is correct

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