Question

Sunil sells his bike worth Rs. 25000 to Rohit
at a profit of 20%. After 6 months Rohit sells
the bike back to Sunil at a loss of 20%. Find
the total profit percent of Sunil considering
both the transactions.​

Answer 1

Answer:

Total Profit = ₹6,000

Step-by-step explanation:

$\implies$ $SP\:=\:\Large\frac{100+P}{100}$$×CP$

$\implies$ $SP\:=\:\Large\frac{120}{100}$$×25,000$

$\implies$ $SP\:=\:30,000$

SP of sunil becomes the CP of Rohith so,

$\implies$ $SP\:=\:\Large\frac{100-L}{100}$$×CP$

$\implies$ $SP\:=\:\Large\frac{80}{100}$$×30,000$

$\implies$ $SP\:=\:24,000$

Difference in the prices :

$\implies$ $30,000-24,000$

$\implies$ $\large\boxed{6,000}$

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Answer 2

Answer:

His total profit is 24%

Step-by-step explanation:

Given,

The original cost of the bike = 25,000 rupees,

Profit earned by Sunil = 20%,

So, the amount of profit Sunil earned in first transaction = 20% of 25000

$=\frac{20\times 25000}{100}$

= 5000 rupees,

i.e. cost price of bike for Rohit = 25,000 + 5000 = 30,000

Now, again loss for Rohit = 20%,

Thus, the selling amount he obtained by selling the bike to Sunil again = 30000 - 20% of 30000

= 30000 - 6000

= 24,000 rupees,

So, the amount of profit Sunil earned in second transaction = 25000 - 24000 = 1000 rupees,

⇒ the total profit he earned = 5000 + 1000 = 6,000

Hence, profit percent of Sunil = $\frac{6000}{25000}\times 100$

$=\frac{600}{25}$

= 24%

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