Question

Sunita is twices as old as brother in 6 years time the sum of their age between 3 years. what are their present age​

Answer 1

Step-by-step explanation:

Suppose the present age of brother is x years

Since present age of Sunita is twice the present age of brother,

=> Present age of Sunita = 2x years

Now,

After 6 years,

Brother's age = x + 6

Sunita's age = 2x + 6

Since after 6 years,the sum of their ages is 39,

=> (x + 6) + (2x + 6) = 39

=> x + 2x + 6 + 6 = 39

=> 3x + 12 = 39

=> 3x = 39 - 12

=> 3x = 27

=> x = 27/3

=> x = 9

So brother's age = x = 9 years

&

Sunita's age = 2x = 2×9 = 18 years.