Suppose a biased coin is tossed 6 times. if the probability of getting a head is 2/3, find 1) the probability of getting a tail , 2) the ptobability that the number of heads is greater than the number of tails , 3) the probability of getting an even number of heads
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hey mate here is ur answer
2 + 2 / 3 = 6
2+2= 6/3
4 / 2
2
2 + 2 / 3 = 6
2+2= 6/3
4 / 2
2
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