Suppose EG = 3, EB = 8, AF = 7, m∠EBG = 19,
m∠EGF = 28, and m∠CAE = 51. Find each value.
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Given : EG = 3, EB = 8, AF = 7, m∠EBG = 19, m∠EGF = 28, and m∠CAE = 51.
To Find : EF , AG , ED , m∠EFG , m∠DFG ,
Solution:
EF is congruent to EG
EG = 3
=> EF = 3
AE = EB given
AE = 8
AG = AE + EG
=> AG = 8 + 3
=> AG = 11
A F = 7
DF = EG = 3
AD = A F - DF = 7 - 3 = 4
m∠EFG = m∠EGF
=> m∠EFG = 28°
m∠EAD = m∠EBG = 19°
m∠DFG + m∠EGF + m∠EAD = 180° Sum of angles of a triangle
m∠EGF = 28° given
m∠DFG + 28° + 19° = 180°
=> m∠DFG = 133°
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Suppose EG = 3, EB = 8, AF = 7
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