Suppose m and n are distinct integers. Can be an integer? Give reasons.
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False .
Explanation:
( 3^m × 2ⁿ )/( 2^m × 3ⁿ )
If m = 2 , n = 3
[ m, n are distinct integers ]
= ( 3² × 2³ )/( 2² × 3³ )
= ( 2^3-2 )/( 3^3-2 )
= 2/3 is not an integer
Therefore ,
If m, n are distinct integers ,
( 3^m × 2ⁿ )/( 2^m × 3ⁿ ) is not an
integer.
••••
Explanation:
( 3^m × 2ⁿ )/( 2^m × 3ⁿ )
If m = 2 , n = 3
[ m, n are distinct integers ]
= ( 3² × 2³ )/( 2² × 3³ )
= ( 2^3-2 )/( 3^3-2 )
= 2/3 is not an integer
Therefore ,
If m, n are distinct integers ,
( 3^m × 2ⁿ )/( 2^m × 3ⁿ ) is not an
integer.
••••
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