Question

The volume of thin brass vessel and the volume of a solid cube are both equal to 1 L. What will be the change in volumes of vessel and the cube on being heated to 25 'C .Given alpha for brass = 1.9 X 10-5/ 'C.

Answer 1

Hey mate,

● Answer-
1.425×10^-6 m^3

● Explaination-
As initial volumes of brass vessel and solid cube is same, change in volumes will be same for both.

Volume strain is related to temperature change as-
∆V/V = 3α∆T
∆V = 3 × α × ∆T × V
∆V = 3 × 1.9×10^-5 × 25 × 10^-3
∆V = 1.425×10^-6 m^3

Change in volume is 1.425×10^-6 m^3 .

Hope this helps...

Answer 2

Given volume of brass vessel = volume of solid cube = 1 liter = 10⁻³m

α for brass = 1.9×10⁻⁵ ⁰C⁻¹.

Temperature T=25⁰C

We know change in volume

ΔV = 3αΔT  ------(A)

Now reducing the above given values in (A) we get,

ΔV = 3× 1.9×10⁻⁵ ×10⁻³ ×25 = 1.43×10⁻⁶ m³