Question

Suppose that an object is heated
to 300f and allowed to Cool in
a room whose air temperature
is 80f. After 10 minutes the
tempperature of the object is
250f. What will be its temperature
after 20 minutes​

Answer 1

Answer:

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Answer 2

Answer:

Initial Temperature= 300°F Temperature after 10minutes= 250°F

Temperature decrease in 10 min = 300-250 = 50.

Therefore, Temperature decrease in 1min= 50/10=5°.

Therefore, Temperature decrease in 20 mins= 5x20=100°.

Therefore, final temperature after 20 mins= 300-100=200°F