Math, asked by GoodMonster, 1 year ago

suppose the function f(x)=x^n, n is not equal 0, is differentiable for x. Then n can be any element of interval
(a) [1,infinity)
(b) (0,infinity)
(c) (1/2,infinity)
(d) None of the above.

Answers

Answered by Shantanubhatt
0
the function f(x)=x^n i differentiable for all value of n due to the property differentiation(x^n) = nx^(n-1)

hence option will be 4

pleas give brainliest
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